In a nutshell, tags allows you to navigate through program code distributed over multiple files effectively. e.g if you see a function call or a struct in e-code and want to "jump" to the definition (which may be in a different file) then you just hit CTRL+] in Vim! Pressing CTRL+t will take you back where you came from. Check out http://vim.wikia.com/wiki/Browsing_programs_with_tags#Using_tags if you want to learn more about how to use tags with Vim.

This utility can generate tags file for your e files. It can either walk through e import order, a directory recursively or all directories on SPECMAN_PATH recursively! The tags file will have tags for struct, unit, types, events, defines, fields, variables, etc.

For help and some examples, just run ctags4e -help.

Hello All,

Following is the einstein's puzzle solved by cadence Incisive92  (solved in less than 3 seconds -> FAST!!!!!!)

Thanks,

Vinay Honnavara

Verification engineer at Keyu Tech

vinayh@keyutech.com

 // Author: Vinay Honnavara

// Einstein formulated this problem : he said that only 2% in the world can solve this problem
// There are 5 different parameters each with 5 different attributes
// The following is the problem

// -> In a street there are five houses, painted five different colors (RED, GREEN, BLUE, YELLOW, WHITE)

// -> In each house lives a person of different nationality (GERMAN, NORWEGIAN, SWEDEN, DANISH, BRITAIN)

// -> These five homeowners each drink a different kind of beverage (TEA, WATER, MILK, COFFEE, BEER),

// -> smoke different brand of cigar (DUNHILL, PRINCE, BLUE MASTER, BLENDS, PALL MALL)

// -> and keep a different pet (BIRD, CATS, DOGS, FISH, HORSES)


///////////////////////////////////////////////////////////////////////////////////////
// *************** Einstein's riddle is: Who owns the fish? ***************************
///////////////////////////////////////////////////////////////////////////////////////

/*
Necessary clues:

1. The British man lives in a red house.
2. The Swedish man keeps dogs as pets.
3. The Danish man drinks tea.
4. The Green house is next to, and on the left of the White house.
5. The owner of the Green house drinks coffee.
6. The person who smokes Pall Mall rears birds.
7. The owner of the Yellow house smokes Dunhill.
8. The man living in the center house drinks milk.
9. The Norwegian lives in the first house.
10. The man who smokes Blends lives next to the one who keeps cats.
11. The man who keeps horses lives next to the man who smokes Dunhill.
12. The man who smokes Blue Master drinks beer.
13. The German smokes Prince.
14. The Norwegian lives next to the blue house.
15. The Blends smoker lives next to the one who drinks water.
*/




typedef enum bit [2:0]  {red, green, blue, yellow, white} house_color_type;
typedef enum bit [2:0]  {german, norwegian, brit, dane, swede} nationality_type;
typedef enum bit [2:0]  {coffee, milk, water, beer, tea} beverage_type;
typedef enum bit [2:0]  {dunhill, prince, blue_master, blends, pall_mall} cigar_type;
typedef enum bit [2:0]  {birds, cats, fish, dogs, horses} pet_type;




class Einstein_problem;

    rand house_color_type house_color[5];
    rand nationality_type nationality[5];
    rand beverage_type beverage[5];
    rand cigar_type cigar[5];
    rand pet_type pet[5];
        rand int arr[5];
    
    constraint einstein_riddle_solver {
    
        
    
        foreach (house_color[i])
            foreach (house_color[j])
               if (i != j)
                house_color[i] != house_color[j];
        foreach (nationality[i])
            foreach (nationality[j])
               if (i != j)
                nationality[i] != nationality[j];
        foreach (beverage[i])
            foreach (beverage[j])
               if (i != j)
                beverage[i] != beverage[j];
        foreach (cigar[i])
            foreach (cigar[j])
               if (i != j)
                cigar[i] != cigar[j];
        foreach (pet[i])
            foreach (pet[j])
               if (i != j)
                pet[i] != pet[j];
    
    
        //1) The British man lives in a red house.
        foreach(nationality[i])
                (nationality[i] == brit) -> (house_color[i] == red);
                
        
        //2) The Swedish man keeps dogs as pets.
        foreach(nationality[i])
                (nationality[i] == swede) -> (pet[i] == dogs);
                
                
        //3) The Danish man drinks tea.        
        foreach(nationality[i])
                (nationality[i] == dane) -> (beverage[i] == tea);
        
        
        //4) The Green house is next to, and on the left of the White house.
        foreach(house_color[i])        
                 if (i<4)
                    (house_color[i] == green) -> (house_color[i+1] == white);
        
        
        //5) The owner of the Green house drinks coffee.
        foreach(house_color[i])
                (house_color[i] == green) -> (beverage[i] == coffee);
                
        
        //6) The person who smokes Pall Mall rears birds.
        foreach(cigar[i])
                (cigar[i] == pall_mall) -> (pet[i] == birds);
        
        
        //7) The owner of the Yellow house smokes Dunhill.
        foreach(house_color[i])
                (house_color[i] == yellow) -> (cigar[i] == dunhill);
        
        
        //8) The man living in the center house drinks milk.
        foreach(house_color[i])
                if (i==2) // i==2 implies the center house (0,1,2,3,4) 2 is the center
                    beverage[i] == milk;
        
        
        
        //9) The Norwegian lives in the first house.
        foreach(nationality[i])        
                if (i==0) // i==0 is the first house
                    nationality[i] == norwegian;
        
        
        
        //10) The man who smokes Blends lives next to the one who keeps cats.
        foreach(cigar[i])        
                if (i==0) // if the man who smokes blends lives in the first house then the person with cats will be in the second
                    (cigar[i] == blends) -> (pet[i+1] == cats);
        
        foreach(cigar[i])        
                if (i>0 && i<4) // if the man is not at the ends he can be on either side
                    (cigar[i] == blends) -> (pet[i-1] == cats) || (pet[i+1] == cats);
        
        foreach(cigar[i])        
                if (i==4) // if the man is at the last
                    (cigar[i] == blends) -> (pet[i-1] == cats);
        
        foreach(cigar[i])        
                if (i==4)
                    (pet[i] == cats) -> (cigar[i-1] == blends);
        
        
        //11) The man who keeps horses lives next to the man who smokes Dunhill.
        foreach(pet[i])
                if (i==0) // similar to the last case
                    (pet[i] == horses) -> (cigar[i+1] == dunhill);
        
        foreach(pet[i])        
                if (i>0 & i<4)
                    (pet[i] == horses) -> (cigar[i-1] == dunhill) || (cigar[i+1] == dunhill);
                    
        foreach(pet[i])        
                if (i==4)
                    (pet[i] == horses) -> (cigar[i-1] == dunhill);
                    


        //12) The man who smokes Blue Master drinks beer.
        foreach(cigar[i])
                (cigar[i] == blue_master) -> (beverage[i] == beer);
        
        
        //13) The German smokes Prince.
        foreach(nationality[i])        
                (nationality[i] == german) -> (cigar[i] == prince);
        

        //14) The Norwegian lives next to the blue house.
        foreach(nationality[i])
                if (i==0)
                    (nationality[i] == norwegian) -> (house_color[i+1] == blue);
        
        foreach(nationality[i])        
                if (i>0 & i<4)
                    (nationality[i] == norwegian) -> (house_color[i-1] == blue) || (house_color[i+1] == blue);
        
        foreach(nationality[i])        
                if (i==4)
                    (nationality[i] == norwegian) -> (house_color[i-1] == blue);
        

        //15) The Blends smoker lives next to the one who drinks water.            
        foreach(cigar[i])            
                if (i==0)
                    (cigar[i] == blends) -> (beverage[i+1] == water);
        
        foreach(cigar[i])        
                if (i>0 & i<4)
                    (cigar[i] == blends) -> (beverage[i-1] == water) || (beverage[i+1] == water);
                    
        foreach(cigar[i])        
                if (i==4)
                    (cigar[i] == blends) -> (beverage[i-1] == water);
        
    } // end of the constraint block
    


    // display all the attributes
    task display ;
        foreach (house_color[i])
            begin
                $display("HOUSE : %s",house_color[i].name());
            end
        foreach (nationality[i])
            begin
                $display("NATIONALITY : %s",nationality[i].name());
            end
        foreach (beverage[i])
            begin
                $display("BEVERAGE : %s",beverage[i].name());
            end
        foreach (cigar[i])
            begin
                $display("CIGAR: %s",cigar[i].name());
            end
        foreach (pet[i])
            begin
                $display("PET : %s",pet[i].name());
            end
        foreach (pet[i])
            if (pet[i] == fish)
                $display("THE ANSWER TO THE RIDDLE : The %s has %s ", nationality[i].name(), pet[i].name());
    
    endtask // end display
    
    
endclass




program main ;

    initial
        begin
            Einstein_problem ep;
            ep = new();
            if(!ep.randomize())
                $display("ERROR");
            ep.display();
        end
endprogram // end of main

        

Hi all 

Good day.

Can anyone tell me whether it is possible to view the signals once it is modified from its previous values without closing the simvision window. If possible kindly let me know the command for it(Linux).

 Is it possible to view the schematic for the code written?? Kindly instruct me.

 Thanks all.

S K S 

Hello,

 I am working in a digital design. The functional, post synthesis and post P&R without IO pads are all working fine, i.e., functionally and with clean timing reports "no setup/hold violations". I just added the IO pads to the same design, I had to change the timing constraints a bit for the synthesis but I have a clean design at SOC Encounter, i.e., clean DRC and clean timing reports "no setup/hold violations". However, when I perform simulation using the exported net-list from SOC Encounter together with SDF exported from the same tool, I got a lot of hold violations. Consequently, the design is not funcitioning.

Why and how I can overcome or trobleshoot this issue?

In waiting for your feedback and comments.

Regards.

Attached is the latest emacs mode for e/Specman - version 1.23

Please follow the install instructions in the top section of the actual file
(after unzipping it) to install/load this package with your emacs.

Hello,

I have a question I want to create a cover that consists a sparse values, pre-computed (a list or define) for example l = {1; 4; 7; 9; 2048; 700} I'd like to cover that data a (uint(bits:16)) had those values, Any suggestion on how to achieve this, I'd prefer to stay away from macros, and avoid to write a lot of code

struct inst {

  data :uint(bits:16);
  opcode :uint(bits:16);
  !valid_data : list of uint(bits:16) = {0; 12; 10; 700; 890; 293;};
  event data_e;
  event opcode_e;

  cover data_e is {
     item data using radix = HEX, ranges = {
     //I dont want to write all of this
     range([0], "My range1");
     range([10], "My range2");
     //... many values in between
    range([700], "My rangen");
    };

    item opcode;

   cross data, opcode;
};

post_generate() is also {
    emit data_e;
};
};

Hi all, I've trained a device model with the approach of an artificial neural network, and it shows well fit. 

May I know how to transfer the trained model to Verilog-A, so that, we can use this model to do circuit simulation?

And I've searched for some lectures that provide the Verilog-A code in the appendix, but I'm freshman in the field of Verilog-A, 

could anyone tell me each statement? such as

real hlayer-w[0:(NI*NNHL)-1   

Modified version of shr_ram from erm_lib to support mvl_values
regards: snaptube

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Do you know if it is possible to define localized back etching (LBE) in EMX? It should be associated to a layer which defines the holes done in the substrate. I've not found any reference for this in the .proc syntax. 

--> Answer found. This is not possible because EMX considers the same dielectric in all x-y plane

Hi! I'm using EMX with 2 design kits. In one works fine. With another, I do not see the mesh or current view. The menu item is not shown. This happens only with one DK. With the other one I'm able to run Paraview without any issue. 

Besides, I would like to know if there is any way to see the 3D view without mesh and current. Just a nice 3D view. 

I've also tried to install the latest version (EMX2023_2) but nothing changes. 

Hello Team,
I am currently following this AWR script posted on them, to run a python script directly from inside AWR using VBA script.

Launching Python from AWRDE VBA Script - AWR Scripts - AWR Knowledgebase

Following all the basic steps with no changes to the code. I have Vscode and python-3.12.2 installed in my system. 

This is the error I am getting while running this code. 

Thank you for your help 

Best Regards

SID

Hi, I would be grateful if you can help me with this error which I get after trying to run an EMX simulation on a PCELL.

I've found very limited information in this forum. Thanks

Hi,

My Virtuoso and Spectre Version: ICADVM20.1-64b.NYISR30.2

I have an expression where the EvalType is "sweeps". Here is the expression (I also attached the snapshot):

(peakToPeak(leafValue(swapSweep(delay(?wf1 clip((VT("/clk0") - VT("/clk180")) (VAR("mt_stop") - (4.0 / VAR("datarate"))) VAR("mt_stop")) ?value1 0 ?edge1 "rising" ?nth1 1 ?td1 0 ?tol1 nil ?wf2 clip((VT("/tx_padp") - VT("/tx_padn")) (VAR("mt_stop") - (4.0 / VAR("datarate"))) VAR("mt_stop")) ?value2 0 ?edge2 "rising" ?nth2 1 ?tol2 nil ?td2 nil ?stop nil ?multiple nil) "VDD_FIXED_NOISE") "VREGLN_cmode" 0.85 "VREGDRV_novn" 0.4 "datarate" 1.658e+10) ?overall t) / 10.0)

What this expression does is that it compares the delay between the output data with respect to a reference clock. I then get this information for two conditions (VDD_FIXED_NOISE = 0 or 10mV) to get the effect of the supply-induced jitter. In the expression, I need to give the value of each parameter in different modes to distinguish them from each other. Now I want to sweep the base supply values and see the supply variation effects. For example, I want to change VREGLN_cmode from 0.85 to 0.81 and see how my supply-induced jitter changes. For that, the hard way is to copy the expression and change that value accordingly (e.g. "VREGLN_cmode" 0.81). I'm looking for an easier way to use a variable in the expression. Something like VAR("VREGLN_Sweep"). But I see it doesn't work in my expression and it gives an eVal error. I tested this before in other expressions (not sweep type) and it always worked. I have only one test and these variables are all Design Variables and not Global variables.
I want to know what mistake am I doing here and is there a way to make this work. Sorry that if I could not explain better my inquiry. Thank you.

Hi, 
In the MATLAB, I am using cds_srr and cds_innersrr commands. Although I set the path to the spectre root, I face this error:

One or more output arguments not assigned during call to "cds_innersrr".

Error in cds_srr (line 20)
sig = cds_innersrr(dirname, dataset, signame, verbose);

Error in techsweep_spectre_run (line 64)
struct_n = cds_srr(c.outfile, c.sweep, params_n{1});

I would highly appreciate it if you could help me.

Hi,
My Virtuoso and Spectre Version: ICADVM20.1-64b.NYISR30.2
I plot an eye diagram using a built in function. I want to see the data-dependent jitter. I want to measure the eye diagram edges at zero crossing (width of that diamond part) shown in the pic by vertical and horizontal markers. I can put a marker and read the numbers there and get what I want. But now I want to run Monte Carlo and I can't do this for all samples. I wish I could write an expression for this. Unfortunately, I see that the function "cross" is not working on the eye diagram. Basically, when I send the eye diagram data to a table, I see that it actually is just the prbs data and not the eye diagram data. Is there a hack that can help me achieve my goal which is: having an expression to measure the edges of the eye diagram at zero crossing?
There is a script that Andrew wrote (https://support.cadence.com/wps/mypoc/cos?uri=deeplinkmin%3AViewSolution%3BsolutionNumber%3D11395772). This is a good script but it puts all edges on top of each other. I want to distinguish the two edges. In the attached pic (two-period eye diagram) you can see what I mean by the two edges (diamond shapes). I want to measure each of the two and take the maximum. Having all the edges on top of each other won't give me what I want. All edges together will lso include DCD. I purely want to measure DDJ. DCD is measured separately. I have very little experience with writing scripts and could not modify Andrew's script.
Your help is much appreciated. Thank you.

Hello,

I am trying to design an RF mixer for a TX.
Assume my input IF signal is at 1 GHz, my LO at 2 GHz and I want my RF at 3 GHz, and assume that the mixer fully works after testing it with HB.
How to simply set the envelope analysis to check the EVM ?
I read through the documentation but I couldn't get it (I couldn't fully understand the settings of the source, probe, analysis.)
Which source and probe to use? I want custom modulation with custom bandwidth and center frequency.
Is there some examples for the ENVLP analysis ?

I am using IC23.1 and spectre 20.1.354.

Hi,

In our design team, we're looking for a strategy to make all cell views self-contained. We are struggling to do so when nport devices are involved.

The nport file requires a full path, whereas what we need is a relative path to the current path of the cell in which we're using the nport.

I have browsed through the forums & cadence support pages, but could not find a solution.

1) There is a proposal from Andrew to add the file directory in ADE option "Simulation Files." :https://community.cadence.com/cadence_technology_forums/f/rf-design/27167/s-parameter-datafile-path-in-nport . This, however, is not suitable, because the cell is not self contained.

2) The new cadence version off DataSource "cellView" in nport options:

This however is not suitable for us due to two reasons:

i- Somehow we don't get this option in the nport cell (perhaps some custom modification from our PDK team)

ii- Even if we had this option, it requires to select the library, which again makes it unsuitable: We often copy design libraries for derivative products using "Hierarchical Copy" feature. And when the library is copied, the nport will still be pointing to the old library. Thus, it is still not self-contained.

In principle, it should not be difficult (technically) to point to a text file relative to the cell directory (f.ex we can make a folder under the same cell with name "sparFiles" & place all spar files under this folder), however it does not seem to be possible.

Could you perhaps recommend us a work-around to achieve our goal: making the cells which contain nport devices self-contained so that when we copy a cell, we do not have to update all the nport file destinations ?

Thanks in advance.

My Cadence Version: IC23.1-64b.ISR4.51

My Spectre version: 23.1.0.362.isr5

I want to plot the inductance through formula L1=(imag(Z(1,1))/(2*pi*freq)), but the system tells me that the freq is unbound variable? What can I do?

Hi *,

I am simulating a 32kHz high Q crystal oscillator with a pulse shaping circuit. I set up a PSS analysis using the Shooting Newton engine. I set a beat frequency of 32k and used the crystal output and ground as reference nodes. After the initial transient the amplitude growth was already pretty much settled such that the shooting iterations could continue the job.

My problem is: In 5...10% of my PVT runs the simulator detects a frequency divider in the initial transient simulation. The output log says:

Frequency divided by 3 at node <xxx>

The Estimated oscillating frequency from Tstab Tran is = 11.0193 kHz .

However, the mentioned node is only part of the control logic and is always constant (but it has some ripples and glitches which are all less than 30uV). These glitches spoil my fundamental frequency (11kHz instead of 32kHz). Sometimes the simulator detects a frequency division by 2 or 3 and the mentioned node <xxx> is different depending on PVT - but the node is always a genuine high or low signal inside my control logic.

How can I tell the simulator that there is no frequency divider and it should only observe the given node pair in the PSS analysis setup to estimate the fundamental frequency? I have tried the following workarounds but none of them worked reliably:

- extended/reduced the initial transient simulation time

- decreased accuracy

- preset override with Euler integration method for the initial transient to damp glitches

- tried different initial conditions

- specified various oscillator nodes in the analysis setup form

By the way, I am using Spectre X (version 21.1.0.389.ISR8) with CX accuracy.

Thanks for your support and best regards

Stephan

I get multiple results at the same frequency in a 3-tone simulation.

I try to determine the IP3 of a mixer. I have 3 large signal tones: 0.75 GHz, 1.25 GHz and 1.26 GHz.

At the IM3 frequency of 490 MHz I observe 4 results, see also the screenshot of the table output. The frequencies are exactly the same (even when I subtract 490 MHz by using xval() ).

Which of the values do I have to use to determine the correct IP3?

Is there an option to merge these results?

Hello everyone,

I am trying to perform a load pull simulation of a transistor to verify some gain calculations I made using its S-parameters. Specifically, I have calculated the optimal conjugate impedances for the input and output to later calculate the power dissipated and transmitted in each stage of the transistor. Then, I only varied the output impedance and recalculated these powers, noticing that the power delivered to the load is lower.

Now, what I want to do is simulate this behavior using the Load Pull simulation. I have taken the model shown in the image, but I believe it is a linear model. My question is: if the chosen model is linear, is the load pull simulation accurate? In the calculations I made, nonlinearities are not considered. I don’t want to take nonlinearities into account.

In short, do you have any ideas on how to verify the calculations made with the transistor’s S-parameters through a load pull simulation?

Can you recommend any transistor model that is nonlinear and also has an S-parameter file?

Thank you very much in advance.

While adding an element created from a netlist file in AWR, I am getting the error 'The element type being dropped is not compatible with the window it is being dropped into'. The netlist file in AWR has the following contents:

.subckt BFG520W base collector emitter npn
.model BFG520W NPN(IS=1.016E-15 NF=1.000 BF=220.1 IKF=510E-3 VAF=48.06
+ ISE=2.83E-13 NE=2.035 NR=0.988 BR=100.7 IKR=2.352E-3
+ VAR=1.692 ISC=24.48E-18 NC=1.022 RB=10.00 RE=0.7753
+ RC=2.21 CJC=447.6E-15 MJC=0.07 VJC=0.1892
+ CJE=1.245E-12 TF=8.616E-12 TR=5.437E-12 mfg=NXP)

I have attached screenshots of the element BFG520W2 created due to the above netlist and the error I am getting while adding this element.

Hello everyone,

For my cross-coupled oscillator design, I have a problem with stability analysis. Based on my achieved results which are attached, where is my design problem?

Best,

https://ibb.co/bgKFP4N

https://ibb.co/3FGRLmV

https://ibb.co/pwSZDSF

Hi I noticed that some figures from the old posts in the cadence blogs have been missing.

I think this problem happened before and Andrew Beckett asked the original author to fix the issue:

 Figures missing in the RF Design Blogs article of "Measuring Fmax for MOS Transistors" 

Some of these posts are quite valuable, and would be nice to have access to the figures, which are a very important part of some posts,

Thanks

Leandro

Sample clues

18 across: Makoto Hagiwara and David Jung both claim to have invented it (7,6)

1 down: French impressionist who rejected that term (5)

3 down: Artificial surface used for playing hockey (9)

7 down: The sequel to Iliad (7)

12 down: Adipose tissue (4,3)

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6 across: Franchise revived by Frank Miller (6)

13 across: What Keanu Reeves and Zayed Khan have in common (5)

18 across: What Frank Sinatra and George Clooney have in common (6,6)

19 across: Dosa mix, for example (6)

2 down: Green, in a non-environmental way (7)

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5 down: Torso covering (6)

7 down: Government by rogues (12)

15 across: eBay speciality (7)

18 across: Demonic (8)

20 across: Common language (6,6)

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17 across: Beckham speciality (4,4)

4 down: Havana speciality (5)

19 across: Infamous 1988 commercial against Michael Dukakis (9,4)

11 down: Precisely (2,3,3)

13 down: City infamously ransacked by the Japanese in 1937 (7)

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11 across: Chandigarh’s is 0172 (3,4)

21 across: He’s a loser, baby (4)

1 down: Garment meant to shape the torso (6)

12 down: It’s slogan: “Life, Liberty and the Pursuit” (8)

18 down: Noise made by badminton players? (6)

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Sample clues

5 across: The US president’s bird (3,5,3)

11 down: Group once known as the Quarrymen (7)

10 across: Cavalry sword (5)

19 across: Masonic ritual (5,6)

1 down: Pioneer of Ostpolitik (6)

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Sample clues

14 across: FDR’s baby (3,4)

1 down: A glitch in the Matrix? (4,2)

4 down: Slanted character (6)

5 down: New Year’s venue in New York (5,6)

16 down: Atmosphere of melancholy (5)

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Sample clues

6 across: Alejandro González Iñárritu’s breakthrough film (6,6)

19 across: Soft leather shoe (8)

7 down: Randroids, for example (12)

12 down: First American World Chess Champion (7)

17 down: Circle of influence (5)

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Sample clues

5 across: Robbie Robertson song about Richard Manuel (6,5)

2 down: F5 on a keyboard (7)

10 across: Lionel Richie hit (5)

3 down: ALTAIR, for example (5)

16 down: The problem with Florida 2000 (5)

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Sample clues

9 across: Van Morrison classic from Moondance (7)

6 down: Order beginning with ‘A’ (12)

6 across: Fatal weakness (8,4)

19 across: Rolling Stones classic (12)

4 down: Massacre tool (8)

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