Virtuoso Studio IC23.1 ISR8 production release is now available for download.(read more)

This blog explores how Virtuoso Studio Net Tracer can help you perform a design review.

We’ll use the net connectivity option, which allows the user to get a clean highlighted net. You can use the Net Tracer tool to highlight the nets. You can find the Net Tracer command under the connectivity pulldown menu in the layout window.

Trace manager and the ability to display different islands on the same net with other colors, you can identify and connect the unconnected islands as you wish.

The Net Tracer utility traces the nets in the physical view (layout). The trace is a highlighted net, which is a non-selectable object. The Net Tracer utility is available from Virtuoso Layout Suite XL onwards. You can use this utility based on your specific needs and preferences.

For a better understanding of the Net Tracer feature, let’s see one scenario between the circuit designer and layout engineer for a layout design review.

Circuit designer: Can we go through the routed input nets “inm” and “inp”?

Layout engineer: From the below layout view where they are highlighted using the XL connectivity, today I will use Net Tracer utility for the design review.

Circuit designer: I have never heard of this feature. Let's see how it works.

Layout engineer: Sure, now we turn on the Net Tracer toolbar using the below option.

You see the Net Tracer options form here:

As you can see on my screen, I have opened the layout view and engaged the Net Tracer utility.

Net Tracer allows shapes to be traced on a net in two tracing modes, namely, physical and logical, where shapes on the same net are physically or logically connected.

Physical tracing gathers all the shapes physically connected on the same net.

Logical tracing gathers all the shapes assigned to the same net. It highlights the net as in the source design (schematic). It will highlight shapes on the same net, even if they are isolated shapes that are not physically connected.

For this scenario, let us use physical tracing for input nets “inm” and “inp."

Highlighted nets are shown below:

Net “inm”                    Net “inp”                   Nets “inm” and “inp” 

Net Tracer has features like physical and logical tracing, preview, step-by-step mode, ease of tracing a net on a shape out of multiple underlying shapes, and so on.

Let us explore logical tracing for output nets “outm” and “outp”:

Here, you can see how to enable true color and halo before enabling logical tracing to identify the metal route. After enabling the true color halo, enable the logical trace.

Here, I am opening the trace manager to search “outm” and “outp” and click trace. That will trace the particular nets as shown.

Net Tracer has a preview feature, which is helpful in terms of the number of previewed objects. This preview capability hints at how the trace would appear when you create it. This useful feature in Virtuoso Studio highlights both completed and incomplete nets, helping the user better understand the status of the highlighted nets.

Circuit designer: Thanks for the design review. You have done good work. Net Tracer clearly shows both types of tracing, and it was even easy for the circuit designer to understand.

Layout engineer: Let me share the link to the Net Tracer RAK, where other layout engineers can explore many more amazing features of the Net Tracer.

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Virtuoso Studio IC23.1 ISR9 production release is now available for download.(read more)

Virtuoso Studio IC23.1 ISR10 production release is now available for download.(read more)

Hi

In the environment I'm currently working, axes are shown for schematic, symbol, and layout views.For schematics and symbols, I'd prefer a dim gray, such that the axes are just visible but not dominant. For the layout, I'd prefer a brighter color. Is there a way to realize this? So far when I change the color of the 'axis' layer in the display resource editor, the axes in all three views get changed together:

Thanks very much for your input!

I want to use PSpice model (download from TI) in Virtuoso , but it can not work. Please help me to check the error message, Thanks

ADE-> Setup-> simulation files->Pspice  Files  /TPS628502-Q1_TRANS.LIB

Parse error before token ']' in expression '[[STEADY_STATE]*0.6]'. If '[[STEADY_STATE]*0.6]'  is a spice expression, quotes are required for the expression.

ERROR(SFE-46): An instance of 'TPS628502-Q1_TRANS'  can have at most 8 terminals (but has 9).

*****************************************************************************
.SUBCKT TPS628502-Q1_TRANS COMP_FSET EN FB GND PG SW SYNC_MODE VIN
+ PARAMS: STEADY_STATE=0
V_U9_V45 U9_N16725824 0 5
E_U9_ABM22 U9_N16725392 0 VALUE { V(FREQ)*1e-12 }
X_U9_U161 U9_N16849713 U9_N16846056 one_shot PARAMS: T=20

Hi

I have a rather strange question - is there a way to tell layout XL to NOT place the error/warning markers on a design when I open a cell?  I do a lot of my layout by using arrays from placed instances and create mosaics that completely ignore the metadata that Layout XL uses with its bindings with schematic (and instances get deleted etc. but I do like using it to generate all my pins etc.) and it's just really annoying when I open a design that I know is LVS clean and since the connectivity metadata is all screwed up (because I did not use it to actually complete the layout) I have a design that's just blinking at me at every gate, source and drain.  I typically delete them at the high level heirarchically but the second I go in and modify something and come back up it places all of them again.  I know that if I flatten all the p cells it goes away but sometimes it's nice to have that piece of metadata but that's about it.  Is there a way to "break" the features of XL like this?  I realize what a weird question this is but it's becoming more of an issue since we moved to IC 23 from IC 6 where there is no longer a layout L that I can use free from these annoyances that can't use any of the connectivity metadata.

Thanks

Chris

Hello All,

Following is the einstein's puzzle solved by cadence Incisive92  (solved in less than 3 seconds -> FAST!!!!!!)

Thanks,

Vinay Honnavara

Verification engineer at Keyu Tech

vinayh@keyutech.com

 // Author: Vinay Honnavara

// Einstein formulated this problem : he said that only 2% in the world can solve this problem
// There are 5 different parameters each with 5 different attributes
// The following is the problem

// -> In a street there are five houses, painted five different colors (RED, GREEN, BLUE, YELLOW, WHITE)

// -> In each house lives a person of different nationality (GERMAN, NORWEGIAN, SWEDEN, DANISH, BRITAIN)

// -> These five homeowners each drink a different kind of beverage (TEA, WATER, MILK, COFFEE, BEER),

// -> smoke different brand of cigar (DUNHILL, PRINCE, BLUE MASTER, BLENDS, PALL MALL)

// -> and keep a different pet (BIRD, CATS, DOGS, FISH, HORSES)


///////////////////////////////////////////////////////////////////////////////////////
// *************** Einstein's riddle is: Who owns the fish? ***************************
///////////////////////////////////////////////////////////////////////////////////////

/*
Necessary clues:

1. The British man lives in a red house.
2. The Swedish man keeps dogs as pets.
3. The Danish man drinks tea.
4. The Green house is next to, and on the left of the White house.
5. The owner of the Green house drinks coffee.
6. The person who smokes Pall Mall rears birds.
7. The owner of the Yellow house smokes Dunhill.
8. The man living in the center house drinks milk.
9. The Norwegian lives in the first house.
10. The man who smokes Blends lives next to the one who keeps cats.
11. The man who keeps horses lives next to the man who smokes Dunhill.
12. The man who smokes Blue Master drinks beer.
13. The German smokes Prince.
14. The Norwegian lives next to the blue house.
15. The Blends smoker lives next to the one who drinks water.
*/




typedef enum bit [2:0]  {red, green, blue, yellow, white} house_color_type;
typedef enum bit [2:0]  {german, norwegian, brit, dane, swede} nationality_type;
typedef enum bit [2:0]  {coffee, milk, water, beer, tea} beverage_type;
typedef enum bit [2:0]  {dunhill, prince, blue_master, blends, pall_mall} cigar_type;
typedef enum bit [2:0]  {birds, cats, fish, dogs, horses} pet_type;




class Einstein_problem;

    rand house_color_type house_color[5];
    rand nationality_type nationality[5];
    rand beverage_type beverage[5];
    rand cigar_type cigar[5];
    rand pet_type pet[5];
        rand int arr[5];
    
    constraint einstein_riddle_solver {
    
        
    
        foreach (house_color[i])
            foreach (house_color[j])
               if (i != j)
                house_color[i] != house_color[j];
        foreach (nationality[i])
            foreach (nationality[j])
               if (i != j)
                nationality[i] != nationality[j];
        foreach (beverage[i])
            foreach (beverage[j])
               if (i != j)
                beverage[i] != beverage[j];
        foreach (cigar[i])
            foreach (cigar[j])
               if (i != j)
                cigar[i] != cigar[j];
        foreach (pet[i])
            foreach (pet[j])
               if (i != j)
                pet[i] != pet[j];
    
    
        //1) The British man lives in a red house.
        foreach(nationality[i])
                (nationality[i] == brit) -> (house_color[i] == red);
                
        
        //2) The Swedish man keeps dogs as pets.
        foreach(nationality[i])
                (nationality[i] == swede) -> (pet[i] == dogs);
                
                
        //3) The Danish man drinks tea.        
        foreach(nationality[i])
                (nationality[i] == dane) -> (beverage[i] == tea);
        
        
        //4) The Green house is next to, and on the left of the White house.
        foreach(house_color[i])        
                 if (i<4)
                    (house_color[i] == green) -> (house_color[i+1] == white);
        
        
        //5) The owner of the Green house drinks coffee.
        foreach(house_color[i])
                (house_color[i] == green) -> (beverage[i] == coffee);
                
        
        //6) The person who smokes Pall Mall rears birds.
        foreach(cigar[i])
                (cigar[i] == pall_mall) -> (pet[i] == birds);
        
        
        //7) The owner of the Yellow house smokes Dunhill.
        foreach(house_color[i])
                (house_color[i] == yellow) -> (cigar[i] == dunhill);
        
        
        //8) The man living in the center house drinks milk.
        foreach(house_color[i])
                if (i==2) // i==2 implies the center house (0,1,2,3,4) 2 is the center
                    beverage[i] == milk;
        
        
        
        //9) The Norwegian lives in the first house.
        foreach(nationality[i])        
                if (i==0) // i==0 is the first house
                    nationality[i] == norwegian;
        
        
        
        //10) The man who smokes Blends lives next to the one who keeps cats.
        foreach(cigar[i])        
                if (i==0) // if the man who smokes blends lives in the first house then the person with cats will be in the second
                    (cigar[i] == blends) -> (pet[i+1] == cats);
        
        foreach(cigar[i])        
                if (i>0 && i<4) // if the man is not at the ends he can be on either side
                    (cigar[i] == blends) -> (pet[i-1] == cats) || (pet[i+1] == cats);
        
        foreach(cigar[i])        
                if (i==4) // if the man is at the last
                    (cigar[i] == blends) -> (pet[i-1] == cats);
        
        foreach(cigar[i])        
                if (i==4)
                    (pet[i] == cats) -> (cigar[i-1] == blends);
        
        
        //11) The man who keeps horses lives next to the man who smokes Dunhill.
        foreach(pet[i])
                if (i==0) // similar to the last case
                    (pet[i] == horses) -> (cigar[i+1] == dunhill);
        
        foreach(pet[i])        
                if (i>0 & i<4)
                    (pet[i] == horses) -> (cigar[i-1] == dunhill) || (cigar[i+1] == dunhill);
                    
        foreach(pet[i])        
                if (i==4)
                    (pet[i] == horses) -> (cigar[i-1] == dunhill);
                    


        //12) The man who smokes Blue Master drinks beer.
        foreach(cigar[i])
                (cigar[i] == blue_master) -> (beverage[i] == beer);
        
        
        //13) The German smokes Prince.
        foreach(nationality[i])        
                (nationality[i] == german) -> (cigar[i] == prince);
        

        //14) The Norwegian lives next to the blue house.
        foreach(nationality[i])
                if (i==0)
                    (nationality[i] == norwegian) -> (house_color[i+1] == blue);
        
        foreach(nationality[i])        
                if (i>0 & i<4)
                    (nationality[i] == norwegian) -> (house_color[i-1] == blue) || (house_color[i+1] == blue);
        
        foreach(nationality[i])        
                if (i==4)
                    (nationality[i] == norwegian) -> (house_color[i-1] == blue);
        

        //15) The Blends smoker lives next to the one who drinks water.            
        foreach(cigar[i])            
                if (i==0)
                    (cigar[i] == blends) -> (beverage[i+1] == water);
        
        foreach(cigar[i])        
                if (i>0 & i<4)
                    (cigar[i] == blends) -> (beverage[i-1] == water) || (beverage[i+1] == water);
                    
        foreach(cigar[i])        
                if (i==4)
                    (cigar[i] == blends) -> (beverage[i-1] == water);
        
    } // end of the constraint block
    


    // display all the attributes
    task display ;
        foreach (house_color[i])
            begin
                $display("HOUSE : %s",house_color[i].name());
            end
        foreach (nationality[i])
            begin
                $display("NATIONALITY : %s",nationality[i].name());
            end
        foreach (beverage[i])
            begin
                $display("BEVERAGE : %s",beverage[i].name());
            end
        foreach (cigar[i])
            begin
                $display("CIGAR: %s",cigar[i].name());
            end
        foreach (pet[i])
            begin
                $display("PET : %s",pet[i].name());
            end
        foreach (pet[i])
            if (pet[i] == fish)
                $display("THE ANSWER TO THE RIDDLE : The %s has %s ", nationality[i].name(), pet[i].name());
    
    endtask // end display
    
    
endclass




program main ;

    initial
        begin
            Einstein_problem ep;
            ep = new();
            if(!ep.randomize())
                $display("ERROR");
            ep.display();
        end
endprogram // end of main

        

Using the EMX solver, X-FAB design engineers can efficiently develop next-generation RF technology for the latest communication standards (including sub-6GHz 5G, mmWave, UWB, etc.), which are enabling technologies for communications and electric vehicle (EV) wireless applications. (read more)

With the latest release (Sigrity and Systems Analysis 2022.1 HF2) of Clarity  3D Solver, support for encrypted component models is now available. With this functionality, vendors that supply 3D components, such as connectors, can now merge their...(read more)

Hi,

My Virtuoso and Spectre Version: ICADVM20.1-64b.NYISR30.2

I have an expression where the EvalType is "sweeps". Here is the expression (I also attached the snapshot):

(peakToPeak(leafValue(swapSweep(delay(?wf1 clip((VT("/clk0") - VT("/clk180")) (VAR("mt_stop") - (4.0 / VAR("datarate"))) VAR("mt_stop")) ?value1 0 ?edge1 "rising" ?nth1 1 ?td1 0 ?tol1 nil ?wf2 clip((VT("/tx_padp") - VT("/tx_padn")) (VAR("mt_stop") - (4.0 / VAR("datarate"))) VAR("mt_stop")) ?value2 0 ?edge2 "rising" ?nth2 1 ?tol2 nil ?td2 nil ?stop nil ?multiple nil) "VDD_FIXED_NOISE") "VREGLN_cmode" 0.85 "VREGDRV_novn" 0.4 "datarate" 1.658e+10) ?overall t) / 10.0)

What this expression does is that it compares the delay between the output data with respect to a reference clock. I then get this information for two conditions (VDD_FIXED_NOISE = 0 or 10mV) to get the effect of the supply-induced jitter. In the expression, I need to give the value of each parameter in different modes to distinguish them from each other. Now I want to sweep the base supply values and see the supply variation effects. For example, I want to change VREGLN_cmode from 0.85 to 0.81 and see how my supply-induced jitter changes. For that, the hard way is to copy the expression and change that value accordingly (e.g. "VREGLN_cmode" 0.81). I'm looking for an easier way to use a variable in the expression. Something like VAR("VREGLN_Sweep"). But I see it doesn't work in my expression and it gives an eVal error. I tested this before in other expressions (not sweep type) and it always worked. I have only one test and these variables are all Design Variables and not Global variables.
I want to know what mistake am I doing here and is there a way to make this work. Sorry that if I could not explain better my inquiry. Thank you.

While adding an element created from a netlist file in AWR, I am getting the error 'The element type being dropped is not compatible with the window it is being dropped into'. The netlist file in AWR has the following contents:

.subckt BFG520W base collector emitter npn
.model BFG520W NPN(IS=1.016E-15 NF=1.000 BF=220.1 IKF=510E-3 VAF=48.06
+ ISE=2.83E-13 NE=2.035 NR=0.988 BR=100.7 IKR=2.352E-3
+ VAR=1.692 ISC=24.48E-18 NC=1.022 RB=10.00 RE=0.7753
+ RC=2.21 CJC=447.6E-15 MJC=0.07 VJC=0.1892
+ CJE=1.245E-12 TF=8.616E-12 TR=5.437E-12 mfg=NXP)

I have attached screenshots of the element BFG520W2 created due to the above netlist and the error I am getting while adding this element.

I have been involved in the Virtuoso RF Solution for the last four years. Most of the customers I work with have a SiP package already in progress. They often ask "How do I get my SiP design into Virtuoso RF Solution?" I am excited about new functionality in the latest ICADVM20.1 ISR25 release. It is a new GUI under the Tools menu called Enablement. (read more)

The ICADVM20.1 ISR26 and IC6.1.8 ISR26 production releases are now available for download.(read more)

This blog describes how to efficiently use Virtuoso Visualization and Analysis XL.(read more)

In my last blog, Getting Your Existing SiP File Into Virtuoso RF, I talked about the new enhancements in ICADVM20.1 ISR25 for Virtuoso RF Solution. At the end of the blog, I told you about the Fully Assisted Roundtrip flow, which includes importing SiP files that are compatible with the Virtuoso RF Solution assisted import flow into the Virtuoso platform. Let's examine how the Fully Assisted Roundtrip flow works in this blog.(read more)

The ICADVM20.1 ISR27 and IC6.1.8 ISR27 production releases are now available for download.(read more)

This blog introduces the new Voltus-XFi Custom Power Integrity Solution, a transistor-level EM-IR tool that enables designers to complete comprehensive analysis and debugging easily and quickly.(read more)

This blog helps in demonstrating the use of Pin to trunk routing style which helps in enhancing the layout experience.(read more)

I want to make an opening in the solder mask right above a trace that is acting like a guard ring. Do I really need to go and buy the Allegro Productivity Toolbox add-on for using the Cross-Copy tool for a basic operation like that??

/F

Dear Community,

I have created a PCB board and let's say I have found some parts of the PCB board where there are impedance issues, then how to resolve that impedance issue using the OrCAD X Professional.

Regards,

Rohit Rohan

Has anyone experienced the same situation?

Socionext, a leader in SoC design, recently made significant strides in enhancing its design efficiency for a complex billion-gate project. Faced with the initial challenges of lengthy eight-day iterations and a protracted two-month timing signoff process, the objective was to reduce the iteration cycle to just three days. By integrating Cadence's cutting-edge solutions—Certus Closure Solution, Tempus Timing Solution, and Quantus Extraction Solution—Socionext achieved remarkable improvements.

Notably, the Tempus DSTA tool dramatically cut timing closure time by 73%, outperforming conventional single-machine STA methods. This achievement, combined with the synergistic use of Cadence's Certus Closure and Tempus Timing solutions, allowed Socionext to meet their ambitious three-day iteration target and double productivity. Additionally, integrating these solutions significantly decreased both human and machine resource needs, slashing memory and disk costs by up to 90% and halving engineering resources during the optimization and signoff phases.

For more on this collaboration, check out the "Designed with Cadence" success story video on Cadence's website and YouTube channel.

Also, don't miss the on-demand webinar "Fast, Accurate STA for Large-Scale Design Challenges," which provides a deeper dive into Socionext's breakthroughs and the innovative solutions that powered their success.

The world of electronics design thrives on efficient tools that bridge the gap between concept and silicon. Virtuoso Digital Implementation is a powerful ally for mixed-signal designs, which integrate both analog and digital components. This blog post will examine Virtuoso Digital Implementation's capabilities and explore how it can streamline your mixed-signal design workflow.

Virtuoso Digital Implementation in a Nutshell

Virtuoso Digital Implementation is a license package within the Cadence Virtuoso Design Platform. It offers a streamlined RTL-to-GDSII flow to implement smaller digital blocks within a mixed-signal design environment. Here's what makes Virtuoso Digital Implementation stand out:

• Focus on Small Digital Blocks: Optimized for digital blocks with an instance count of up to 50,000 (expandable to 150,000 with specific configurations), Virtuoso Digital Implementation is ideal for integrating digital logic into your analog-centric design.
• Leveraging Industry Leaders: Virtuoso Digital Implementation utilizes cut-down versions of the renowned Cadence Genus Synthesis Solution and Innovus Implementation System under the hood. This ensures you get access to proven technologies for logic optimization and place-and-route.
• Seamless Integration with the Virtuoso Environment: Virtuoso Digital Implementation's key advantage is its tight integration with the Virtuoso Layout Suite. You can launch the synthesis and place-and-route tools directly from the Virtuoso environment, eliminating the need to switch between platforms.

Benefits of Using Virtuoso Digital Implementation

 By incorporating Virtuoso Digital Implementation into your mixed-signal design flow, you can get several benefits:

• Simplified Workflow: Virtuoso Digital Implementation offers a centralized environment for both digital block implementation and layout editing within the Virtuoso environment. This reduces context switching and streamlines the design process.
• Faster Time-to-Market: Virtuoso Digital Implementation's streamlined workflow can significantly reduce design turnaround times, allowing you to get your product to market quicker.
• Improved Design Quality: Leveraging industry-leading synthesis and place-and-route engines from Cadence ensures high-quality digital block implementation within your mixed-signal design.

Who Should Consider Virtuoso Digital Implementation?

 Virtuoso Digital Implementation is a valuable tool for anyone working on mixed-signal designs with smaller digital blocks. It's particularly well-suited for:

• Analog IC designers who need to integrate digital logic into their designs.
• Circuit design teams working on mixed-signal applications like data converters, power management ICs, and RF transceivers.

Virtuoso Digital Implementation provides a compelling solution for designers working on mixed-signal projects. Its streamlined workflow, tight integration with the Virtuoso design platform, and access to proven digital design tools can significantly improve design efficiency and time-to-market. Virtuoso Digital Implementation is worth considering if you're looking to optimize your mixed-signal design flow.

I am here to help and guide you on how to learn more about Virtuoso Digital Implementation flow.

Welcome to Virtuoso Digital Implementation, an online course recently released. This course teaches implementing digital blocks using Cadence tools based on the Virtuoso Digital Implementation flow. Also, you can download a lab database after the lecture and get hands-on experience in each stage.

Want to Enroll in this Course?

We organize this Virtuoso Digital Implementation training for you as a "Blended" or "Live" training. Please reach out to Cadence Training for further information.

Register for the Online Training with the following steps:

• Log on to cadence.com with your registered Cadence ID and password.
• Select Learning from the menu > Online Courses.
• Search for Virtuoso Digital Implementation using the search bar.
• Select the course and click Enroll.

And don't forget to obtain your Digital Badge after completing the training!

Related Resources

Online Courses

• Cadence RTL-to-GDSII Flow v6.0
• Virtuoso Digital Implementation Training

Training Byte Videos

• How Do You Run Placement Optimization in the Innovus Implementation System?
• How to Run the Synthesis Without DFT?
• How to Run the Synthesis Flow with DFT?
• Creating Power Rings, Power Stripes, and Power Rails in the Innovus Implementation System
• How to Run Power Analysis and Analyze the Results in Innovus?

Happy Learning!

This blog informs about the new badge certification available for Cadence Certus Closure Solution, that grants credit to your proficiency.(read more)

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